Question

Which is the correct relation between ΔG° and Kp?
(A) Kp = [e/RG] to the power of ΔG°
(B) Kp = ΔG°/RT
(C) Kp = e to the power of [-ΔG°/RT]
(D) Kp = - RT log ΔG°

Answer 1

The key equation, ΔG° = -RT

ln K: Important points. R is the gas constant with a value of 8.314 J K-1mol-1.

T is the temperature of the reaction in Kelvin. ΔG° it is important to realise that we are talking about standard free energy change here and free energy change at whatever temperature the reaction was carried out.

Answer 2

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☸ Required Answer is ⬇⬇ ⬇⬇ ⬇


⭕ D) Kp = - RT log ΔG°


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