Question

Which is the correct thermal stability order for H₂E (E = O, S, Se, Te and PO) ?
(1) H₂S < H₂O < H₂Se < H₂Te < H₂Po
(2) H₂O < H₂S < H₂Se < H₂Te < H₂Po
(3) H₂Po < H₂Te < H₂Se < H₂S < H₂O
(4) H₂Se < H₂Te < H₂Po < H₂O < H₂S

Answer 1

The correct thermal stability order of 16th group elements is

$\bold{H_{2}Po<H_{2}Te<H_{2}Se<H_{2}S<H_{2}O}$

Step by step explanation:

• The 16th groups elements are Oxygen,Sulfur, Selenium,Tellurium and Polonium.
• The most common oxidation state of VIA groups elements is +2.
• All these group elements shows +6 oxidation state except for oxygen because absence of "d" electrons.
• The thermal stability of this group is decreases down the group because decreasing M-H bond stability due to increase the size of central atom.
• Therefore, the correct thermal stability order of this group is as follows.
• $\bold{H_{2}Po<H_{2}Te<H_{2}Se<H_{2}S<H_{2}O}$
• Hence, correct option is  -3

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