Question

Which is the equation of a line with a slope of −13 and a y-intercept at (0, 1)?

y=1/3x−1
y=−1/3x+1
y=−3x+1
y=3x−1

PLEASE HELP

Answer 1

$\huge \fcolorbox{sf}{pink}{Solution :)}$

Given ,

• Slope of the line (m) = - 13
• Y intercept is at (0,1) , it means Y intercept (c) = 1

We know that , the slope intercept form is given by

$\large \sf \fbox{y = mx + c}$

Substitute the known values , we get

y = -13x + 1

Hence , the equation of the line is 13x + y - 1 = 0

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