Question

Which is the equation of a trend line that passes through the points (3, 95) and (11, 12)? Round values to the nearest
ten-thousandths.
A y=-10.375x+126.125
B y=-0.096x+13.056
C y = 0.096x+ 10.944
D y=10.375x+63 875​

Answer 1

Answer:

Step 1

we know that

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}m=

x2−x1

y2−y1

we have

A(3,95)\ B(11,12)A(3,95) B(11,12)

Substitute the values

m=\frac{12-95}{11-3}m=

11−3

12−95

m=\frac{-83}{8}m=

8

−83

m=-\frac{83}{8}m=−

8

83

Step 2

Find the equation of the line in point-slope form

y-y1=m(x-x1)y−y1=m(x−x1)

In this problem we have

(x1,y1)=B(11,12)(x1,y1)=B(11,12)

m=-\frac{83}{8}m=−

8

83

substitute

y-12=-\frac{83}{8}(x-11)y−12=−

8

83

(x−11)

y=-\frac{83}{8}x+\frac{83}{8}11+12y=−

8

83

x+

8

83

11+12

y=-10.375x+126.125y=−10.375x+126.125

therefore

the answer is

y=-10.375x+126.125y=−10.375x+126.125