Question

which is the first digit of a smallest 6-digit number formed using the digits 0,1,8,3,9,5?​

Answer 1

Answer:

103589

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Answer 2

The first digit of the smallest number formed using the digits 0,1,8,3,9,5 is 1.

Step-by-step explanation:

In this question, we need to find the first digit of that smallest number which is formed using the digits 0,1,8,3,9,5.

For this let us first understand what is one's place, ten's place etc.

Any number can be written in the expansion form as follows:

Let the number be xyzab

⇒xyzab= (x*10000) + (y*1000)   + (z*100)   +  (a*10) + (b*1)

i.e.

Tth              Th           H            T         O

x*10000      y*1000    z*100     a*10    b*1

where O,T,H,Th,Tth corresponds to one's place, ten's place, hundred's place and so on.

PROCEDURE:

The smallest number is formed by the following the given steps:

(a Place the greatest digits at one's place. i.e. in this case 9

(b) Place The next smaller digit at ten’s place and similarly do this for all the digits till all the given digits have taken their respective places.

(c) The smallest digit is placed at the highest place of the number i.e. 1

Note: We can not place 0 at the highest place because then the number formed will be a 5 digit number.

Hence from the point (c), we see that 1 is the first digit of the smallest number formed.

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