Which is the graph of the linear inequality 2x – 3y < 12?
On a coordinate plane, a solid straight line has a positive slope and goes through (0, negative 4) and (3, negative 2). Everything to the right of the line is shaded.
On a coordinate plane, a dashed straight line has a positive slope and goes through (0, negative 4) and (3, negative 2). Everything to the right of the line is shaded.
On a coordinate plane, a dashed straight line has a positive slope and goes through (0, negative 4) and (3, negative 2). Everything to the left of the line is shaded.
On a coordinate plane, a solid straight line has a positive slope and goes through (0, negative 4) and (3, negative 2). Everything to the left of the line is shaded.
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Given : graph of the linear inequality 2x – 3y < 12
To Find : Choose correct option
Solution:
2x – 3y < 12
2x - 3y = 12
3y = 2x - 12
=> y = 2x/3 - 4
slope = 2/3
+ve slope
2x - 3y = 12
x = 0 => y = - 4
x = 3 => y = - 2
2x – 3y < 12
( 0 , 0) => 0 < 12
Hence origin lies on left side of 2x – 3y = 12
On a coordinate plane, a solid straight line has a positive slope and goes through (0, -4) and (3,-2). Everything to the left of the line is shaded.
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Answer:
-2,-5 1,1 3,5
Step-by-step explanation:
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