Question

which is the largest number that divides 523 and 67 leaving remainder 7 & 1 respectively
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Answer 1

Answer:

Let's split the above question to equations…

Let quotient's be called A and B.

Let the divisor which will be the answer and is constant be X.

Eq 1: (A*X) + 7 = 523.

Eq 2: (B*X) + 1 = 67.

Solving for A*X and B*X we get A*X=516 and B*X=66. The HCF (highest common factor) for 516 and 66 is 6 which is equal to X.

67 by 6 leaves remainder as 1, while 523 by 6 leaves remainder as 7.

Step-by-step explanation:

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