Which is the largest number which divides 77, 147 and 252 leaving same remainder in each case?
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required number = HCF of { b-a, c -b, c -a}
so, HCF of { (147-77) , (252-147), (252-77)}={ 70 , 105 , 175 }
factor of 70 = 2× 5 × 7
factors of 105 = 5 × 7 ×3
factors of 175 = 5 × 7 × 3
so, common factors of all = 35
so, 35 is the answer
so, HCF of { (147-77) , (252-147), (252-77)}={ 70 , 105 , 175 }
factor of 70 = 2× 5 × 7
factors of 105 = 5 × 7 ×3
factors of 175 = 5 × 7 × 3
so, common factors of all = 35
so, 35 is the answer
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nahi aatayar so soory
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