Which is the largest three digit number which when divided by 6 leaves a remainder 5 and when divided by 5 leaves a remainder 3?
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The rule: Consider when N is divided by x the remainder is a and when divided by y the remainder is b. Write them as below:
x y
a b
N = x*y*k + b*x+a, where k=0,1,2,…..
This can be extended into any number of pairs of divisors and remainders.
x*y*z*k + (c*y+b)*x+a
According to this rule, you get 6*5*k + 3*6+5
30*k+23
Now, this is less than 1000
So, k<32.5
=>k = 32
Therefore, the answer is 983.
x y
a b
N = x*y*k + b*x+a, where k=0,1,2,…..
This can be extended into any number of pairs of divisors and remainders.
x*y*z*k + (c*y+b)*x+a
According to this rule, you get 6*5*k + 3*6+5
30*k+23
Now, this is less than 1000
So, k<32.5
=>k = 32
Therefore, the answer is 983.
Answered by
0
Answer: is 9893 buddy hope it helps
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