Question

which is the least -5 disit number which is completely divisible by 61

Answer 1

the least -5 digit number which is completely divisible by 61

so, 10000/61 gives 57 as remainder

so, 10000+4 = 10004/61 which gives 0

so, 10004 is the least number which no remainder

Answer 2

10004 is the ans. quotient 164