which is the least six digit number which when divided by 4,6,10,15 leaves in each case remainder 2 be n.the sum of digits in n is
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LCM of 4, 6, 10, 15 = 60
Least number of 6 digits = 100000
The least number of 6 digits which is exactly divisible by 60
= 100000 + (60 – 40)
= 100020
∴ Required Number = 100020 + 2 = 100022
Hence, the sum of digits
= 1 + 0 + 0 + 0 + 2 + 2 = 5
Least number of 6 digits = 100000
The least number of 6 digits which is exactly divisible by 60
= 100000 + (60 – 40)
= 100020
∴ Required Number = 100020 + 2 = 100022
Hence, the sum of digits
= 1 + 0 + 0 + 0 + 2 + 2 = 5
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