Which is the next year has the same calendar as 2020 .how to identify it ?
Answers
Answer:
find the last day and date of 2020 and matched its first and last date and day with the year2021
Answer:
2048 is the year which has the same calender as 2020.
Step-by-step explanation:
This is a bit hard to understand and confusing but I will try my level best to explain it to you in simply words
We can find the next same year using 'odd days'.
Now, what are odd days?
In a given period, the number of days more than the complete weeks are called odd days.
Here, the period is simply 1 year.
So,
For ex:- In 2001,
There are 365 days, as it is a non leap years,
So, No. of days = 365
Hence, it will have 52 weeks + 1 day
So, In 2001, No. of odd days = 1.
Similarly, In a leap year like 2004,
No. of days = 366
= 52 weeks + 2 days,
Hence,
No. of odd days = 2
So, in simple terms, all non leap year will have 1 odd day, whereas a leap year will have 2 odd days.
Now, if you have grasped this, it's easy forward.
So,
2017 (1 odd day)
2018 (1 odd day)
2019 (1 odd day)
2020 (2 odd days)
When the sum of all the odd days become a multiple of 7, the next year becomes, the next year with the same calendar.
But the important point is, if you are dealing with a leap year, you must see to it that you get a leap year next, or the calender goes wrong from 29th Feb.
So,
2020 (2 odd days)
2021 (1 odd day)
2022 (1 odd day)
2023 (1 odd day)
2024 (2 odd days)
Now, if you add (2 + 1 + 1 + 1 + 2) we get 7, so 2025 has the same day with which 2020 starts, but it is not a leap year, so on 29th Feb. the calender goes wrong.
(Remember to find a leap year simply divide it with 4 and if the remainder is 0, then it's a leap year, if it is a non zero number then, it's a non leap year.)
So, we move forward again.
2025 (1 odd day)
2026 (1 odd day)
2027 (1 odd day)
2028 (2 odd days)
2029 (1 odd day)
2030 (1 odd day)
Now,
If we add we get,
(2 + 1 + 1 + 1 + 2 + 1 + 1 + 1 + 2 + 1 + 1) = 14, 14 is a multiple, so 2031 is the next year starting with the same day as 2020, but again 2031 is not a leap year.
2031 (1 odd day)
2032 (2 odd days)
2033 (1 odd day)
2034 (1 odd day)
2035 (1 odd day)
2036 (2 odd days)
Now, if we add we get,
(2 + 1 + 1 + 1 + 2 + 1 + 1 + 1 + 2 + 1 + 1 + 1 + 2 + 1 + 1 + 1 + 2) = 22 here 22 is not a multiple of 7, so we continue again.
2037 (1 odd day)
2038 (1 odd day)
2039 (1 odd day)
2040 (2 odd days)
2041 (1 odd day)
Now, if we add,
22 + 1 + 1 + 1 + 2 + 1 = 28,
28 is a multiple of 7, so 2042 is the next year with the same starting day as 2020.
But again 2042 is not a leap year.
So,
2042 (1 odd day)
2043 (1 odd day)
2044 (2 odd day)
2045 (1 odd day)
2046 (1 odd day)
2047 (1 odd day)
Now, if we add we get,
28 + 1 + 1 + 2 + 1 + 1 + 1 = 35
35 is a multiple of 7, so 2048 is the year starting with the same day as 2020.
Now, 2048 is a leap hence, 2048 is the next year after 2020 with the same calender.
Now, there as you can see we found it out, but there is a simpler way which if I had said earlier you wouldn't have understood.
If a year is divided by 4,
1) and remainder = 0, then to get next year add 28 years.
2) and remainder = 1, then to get next year add 6 years.
3) and remainder = 2 or 3, then to get next year add 11 years.
You will see why this works if you do it using the 7-multiple method shown above.
Hence,
2048 is the year which has the same calender as 2020.
Hope it helped and believing you understood it........All the best