Question

which is the point of the intersection of x-axis of equation 3x+2y=12




​

Answer 1

$\displaystyle\huge\red{\underline{\underline{Solution}}}$

The given equation of the line is

$3x+2y = 12 \: \: .......(1)$

The equation of x-axis is

$y = 0$

Putting y = 0 in Equation (1) we get

$3x = 12$

$\therefore \: x \: = 4$

So the required point of intersection is ( 4, 0)

Answer 2

Answer:

The given equation of the line is

3x+2y = 12 \: \: .......(1)3x+2y=12.......(1)

The equation of x-axis is

y = 0y=0

Putting y = 0 in Equation (1) we get

3x = 123x=12

\therefore \: x \: = 4∴x=4

So the required point of intersection is (4, 0)