Question

which is the right option ​

Answer 1

Answer:

4

Explanation:

for freezing, energy lowers

$- 3360 \div 273.16 = - 12.25$

so,total energy will be nagetive

∆S=∆H/T

s = -(80cal/g×10g)×4.2(change in joule)

----------------------------

273.16kelvin(0°c)

=. -12.25j/k