Question

Which is the second smallest multiple of 8 that leaves a remainder of 11 when divided by 15?

Answer 1

smallest multiple of 8 will be 56 that is divided by 15 gives remainder 11.

Answer 2

Answer:

The first number smallest multiple of 8 that leaves a remainder of 11 when divided by 15 is 56 and second such number is 176.

Step-by-step explanation:

• We take the multiples of 8, i,e. 8, 16, 24, 32,etc.  and by trial and error method, we note the remainders when the numbers are divided by 15,

• We know that 56 and 176 are  are multiples of 8, and :

(i)         56 = 15 X 3 + 11

(ii)         176 = 15 X 11 + 11

So, both 56 and 176 leaves 11 as remainder when divided by 15.

• Therefore, The first number smallest multiple of 8 that leaves a remainder of 11 when divided by 15 is 56 and second such number is 176.

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