which is the smallest 5 digit no. divisible by 35?
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Smallest 5 digit no=10010.
By trial and error method we see
35*285>10000>35*286
i.e
9975>10000>10010.
So the required no is 10010 which is the smallest 5 digit no divisible by 35.
By trial and error method we see
35*285>10000>35*286
i.e
9975>10000>10010.
So the required no is 10010 which is the smallest 5 digit no divisible by 35.
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