Question

which is the smallest five digit number exactly divisible by 85​

Answer 1

We know that smallest 2 digit number is 10.Smallest three digit number is 100.

Similarly smallest five digit number is 10000.

Here we use, Division algorithm:

Dividend = divisor × quotient + remainder

Dividend = 10000. Divisor = 85

10000 = 85 × 117 + 55

To find required number we have

add number = divisor - remainder. = 85 - 55

= 30 to 10000

Therefore,

Smallest 5 digit number exactly divisible by 85 is 10030.

Verification:

10030 = 85 × 118 + 0

Answer 2

Answer:

17

Step-by-step explanation:

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