Question

Which is the smallest number that can be subtracted from 1936 so that on being divided by 9, 10, 15 the reminder is 7 every time?

Answer 1

Firstly, we will subtract 7 from 1936

=> 1936 - 7 = 1929


Now, we will find the LCM of 9, 10 and 15


9 = 3 × 3

10 = 2 × 5

15 = 3 × 5


LCM = 3 × 3 × 2 × 5

LCM = 90



Now, we will divide 1929 by 90


So, 1929 ÷ 90

= 21.43

Answer 2

$\color{green}Thank \: \: you \: \: for \: \: asking \: \: this \: \: question$

$\color{brown}Good \: \: Morning$

$\color{blue}Namskar$

$\color{yellow}Required \: \: answer$

Step:-1)

Subtract 7 from Given Number (1936)

$\bold{ \boxed{1936 - 7 = 1929}}$

Step:- L.C.M of 9,10,15

L.C.M=90

Step:-3)

Divide 1929 by 90

$\bold{ \boxed{ \frac{1929}{90} }}$

$\bold{\boxed{21.43}}$

$\color{indigo}{Have \: \: a \: \: nice \: \: day}$