Question

which is the smallest rational number -3/4,1/4,0/4-5/4​

Answer 1

Answer

Find two consecutive odd numbers such that two fifths of the smaller number exceeds two ninths of the larger by 4

Solution :

Let one odd number be ' 2n + 1 '

This is smallest odd number .

Other consecutive odd number be ' 2n + 3 '

This is largest odd number .

A/c , " Two fifths of the smaller number exceeds two ninths of the larger by 4 "

First consecutive smallest odd number :

= 2n + 1

= 2(12) + 1

= 24 + 1

= 25 \green{\bigstar}★

Second consecutive largest odd number :

= 2n + 3

= 2(12) + 3

= 24 + 3

= 27 \orange{\bigstar}★

★ ═════════════════════ ★

Alternative : You may solve this question by taking ' x ' as smallest consecutive odd number and ' x + 2 ' as biggest consecutive odd number .

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Answer 2

Given Question :-

Which of the following is smallest rational number

$\sf \: \dfrac{ - 3}{4} , \: \dfrac{1}{4} , \: \dfrac{0}{4} , \: \dfrac{ - 5}{4}$

$\large\underline\purple{\bold{Solution :- }}$

$\rm :\implies\: \boxed{ \pink{ \bf \: \dfrac{ - 3}{4} \: = \tt \: - 0.75 }}$

$\rm :\implies\: \boxed{ \pink{ \bf \: \dfrac{1}{4} \: = \tt \:0.25 }}$

$\rm :\implies\: \boxed{ \pink{ \bf \: \dfrac{0}{4} \: = \tt \: 0}}$

$\rm :\implies\: \boxed{ \pink{ \bf \:\dfrac{ - 5}{4} \: = \tt \: - 1.25}}$

Hence,

• The ascending order is

$\rm :\implies\: \boxed{ \green{ \bf \: \: \tt \: - 1.25 < - 0.75 < 0 < 0.25}}$

So,

$\rm :\implies\: \boxed{ \purple{ \bf \: smallest \: rational\: number \: is \: = \tt \: \dfrac{ - 5}{4} }}$