Chemistry, asked by GingerCrookshanks, 1 year ago

Which is the solubility product expression for PbCl2(s)?

[Pb^2+][Cl^2–]
[Pb+]^2 [Cl–]^2
[Pb^2+][Cl–]^2
[Pb+]^2 [Cl^2–]

Answers

Answered by Anonymous

8

option third is the correct answer✌️✌️✌️

Answered by captainkhan85

6

Pb^2+(aq) + 2 C^l– (aq)

Ksp = [Pb^2+][Cl–]^2

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