Question

Which is true about the completely simplified difference of the polynomials a3b + 9a2b2 − 4ab5 and a3b − 3a2b2 + ab5? The difference is a binomial with a degree of 5. The difference is a binomial with a degree of 6. The difference is a trinomial with a degree of 5. The difference is a trinomial with a degree of 6.

Answer 1

I am not sure about this answer

Answer 2

Thank you for your question:

Here is your answer:

Let be A = a3b + 9a2b2 - 4ab5,

and B = a3b - 3a2b2 + ab5,

The difference can be defined as A - B = a3b + 9a2b2- 4ab5 - (a3b-3a2b2+ab5),

When there is negative sign in front of the para thesis, all the inside signs must change:

That is as follow:

A- B = a3b + 9a2b2- 4ab5 - a3b + 3a2b2 - ab5

= a3b - a3b + 9a2b2+3a2b2 - 4ab5- ab5

= 12a2b2 -5ab5,

the fist term has 2+2=4, as a degree,

the second term has 1 +5 =6,

So the answer is: difference is a binomial with a degree of 6