which law
2x+3=7x-5
By
be written
as
7x-5= 2x+3
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Answer:
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Step-by-step explanation:
f(x)=2x3+7x−5
x=2(f−1(x)3)+7f−1(x)−5
f−1(4)=?
4=2(f−1(4)3)+7f−1(4)−5
2(f−1(4)3)+7f−1(4)−9=0
Let f−1(4)=t
2t3+7t−9=0
2t3−2+7t−7=0
2(t3−1)+7(t−1)=0
2(t−1)(t2+t+1)+7t−1=0
(t−1)(2t2+2t+2+7)=0
t=12t2+2t+9=0
So, f−1(4)=1
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