Which least number should be subtracted from 1000 so that the difference is exactly divisible by 35??
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According to Euclid's division algorithm,
a=bq+r
Where,
a= dividend
b=divisor
q=quotient
And r=remainder.
So let a=1000, b=35,
So we get,
1000= 35×28+20
Subtracting 20 from both sides,
1000–20=35×28+20–20
Thus, 980=35×28
Therefore, as seen above, 980 is perfectly divisible by 35.
And so, 20 is the smallest number to be subtracted.
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