Math, asked by Leeheesung, 6 hours ago

Which list shows the numbers in decreasing order?

a. 2.33…, √4, 7/4, 0, −2
b. √4, 2.33…, 0, −2, 7/4
c. −2, 0, 7/4, √4, 2.33…
d. √4, 0, 7/4, 2.33…, −2​

Answers

Answered by amitnrw
2

Given : list of numbers

To Find : Which list shows the numbers in decreasing order

a. 2.33…, √4, 7/4, 0, −2

b. √4, 2.33…, 0, −2, 7/4

c. −2, 0, 7/4, √4, 2.33…

d. √4, 0, 7/4, 2.33…, −2​

Solution:

a. 2.33…, √4, 7/4, 0, −2

√4 = 2

7/4 = 1.75

2.33... > 2 > 1.75 >  0 > - 2

Hence

2.33…, √4, 7/4, 0, −2   is in descending order

b. √4, 2.33…, 0, −2, 7/4

2 < 2.33

Hence not in descending order

c. −2, 0, 7/4, √4, 2.33…

- 2 < 0

Hence not in descending order

d. √4, 0, 7/4, 2.33…, −2​

0 < 7/4

Hence not in descending order

So correct answer is option a)  2.33…, √4, 7/4, 0, −2  

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Answered by sharonr
1

Answer:

Option(c)

The descending order is -2,0,1.75,2,2.33...

Step-by-step explanation:

Given:

The numbers are

0\\\\-2\\\\\sqrt{4} \\\\\frac{7}{4} \\\\2.33....

We need to arrange in descending order

Writing all numbers in decimal form or integers we get as

0,-2,2,1.75,2.33...

The descending order will be

-2,0,1.75,2,2.33...

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