Question

Which mass of magnesium sulphate will be formed if 12 g of magnesium are reacted with sulphuric acid?

Answer 1

$\bold{Molecular \: mass \: of \: magnesium \: is \: 24g}$

$\bold{Molecular \: mass \: of \: magnesium \: sulphate \: (MgSO_4)}$

Mg = 24g

S = 32g

O=16g

So,

$MgSO_4 = Mg + S + 4O$

On placing values,

$MgSO_4 = 24 + 32 + 4 \times 16$

$MgSO_4 = 56 + 64$

$\bold{MgSO_4 = 120 g}$

According to question,

Magnesium reacts with sulphuric acid to form magnesium sulphate, this happens by displacement reaction.

$Mg + H_2SO_4 \longrightarrow MgSO_4 + H_2$

We can convey that

◼24 g of magnesium forms 120 g magnesium sulphate.

◼ 1 g of magnesium will form =$\dfrac{120}{24} g$ of magnesium sulphate

◼12 g of magnesium will form =$( \dfrac{120}{24} \times 12 )g$ of magnesium sulphate

So,

12 g of magnesium will form

$\huge \boxed{\mathsf{60 g}}$

of magnesium sulphate.