Question

which member of the binomial expansion of (2x³+x–¹)¹⁰ constains x⁶​

Answer 1

Answer:

solution

(10) (2x³)¹¹-k (x-¹)k-¹ =x⁶

k-1

= x³³-³k .x¹-k =x⁶

=33-3k+1-k =6

4k=28

k=7

Step-by-step explanation:

hope it'll help you make it brainliest answer

Answer 2

Step-by-step explanation:

So, coefficient of x40=54.