Question

Which method is used to find the complex root of the equation?

Answer 1

Answer:

the method is numerical

Step-by-step explanation:

suppose we have an equation ax^2+bx+c=0

ax^2+bx+c=0

divided by fromboth side

x^2+(b/a)x+c/a=0

x^2+2x(B/2a)+b^2/4a^2-b^2/4(a)^2=-c/a

{x+b/2a}^2=-c/a+b^2/4(a)^2

=(-4ac+b^2)/4(a)^2

={b^2-4ac}/4(a)^2

x=-b/2a+-under root b^2-4ac/2a

if root is complex than b^2-4ac less than 0 than we get definitely a two complex root

complex root using numerical method