which method of integer wrapper class for converting the value of an object into byte?
Answers
Answer:
That this method can result in a loss of precision if the integer value is too large to fit in a byte. In that case, the most significant bits will be truncated.
Explanation:
From the above question,
In Java, the Byte wrapper category affords a approach referred to as byteValue() which can be used to convert the fee of a Byte object into a byte.
Here's an example:
Byte myByte = 42;
byte myPrimitiveByte = myByte.byteValue();
That this method can result in a loss of precision if the integer value is too large to fit in a byte. In that case, the most significant bits will be truncated.
In this example,
the byteValue() technique is known as on the myByte object to extract its underlying byte value, which is then assigned to the myPrimitiveByte variable.
Note that if the price of the Byte object is backyard the vary of legitimate byte values (-128 to 127), the byteValue() approach will return a truncated value.
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