Chemistry, asked by sushanmanshrestha, 4 months ago

which model of atom is able to overcome the limitation of Rutherford scattering experiment?​

Answers

Answered by dndnfkkvjv
0

Explanation:

The ball is dropped from a point A at a height h above the surface. Thus during the entire motion, let the time taken by the ball to move move from A to B be t¹ from B to C and C to B be t ² , from C to D be t³ , from D to C be t ⁴ , and from B to A be t5

\textsf{Let  T be the time period of the complete motion. }

\textsf{Now for the motion   A to B;       h=0+ [tex]\drac{1}{2}g(t¹) ²}[/tex]

\textsf{⟹t ¹ =  [tex]\drac{√2h}{g}}[/tex]

\textsf{Similarly ,  [tex]t ³= t ⁴=  t 5 =  t ¹ = \drac{√2h}{g}}[/tex]

\textsf{As the time period of the particle executing SHM inside the tunnel is given by      t=2π [tex]\drac{√Re}{g}}[/tex]

\textsf{Thus the time period of the motion of the ball inside the tunnel  i.e   B to C and  C to B,     [tex]t ² =2π \drac{√R}{g}}[/tex]

\textsf{Now the total time period of the motion     T= [tex]t ¹+ t² +  t³+[tex]t⁴+ t5}[/tex]

\textsf{==> T = 2π  [tex]\drac{√R}{g} + 4 \drac{√2h}{g}}[/tex]

Answered by ritikmishara
0

Answer:

vin hi in nwba fa fa of yea in GTA in da I'm waiting on fa

Similar questions