Chemistry, asked by kunaldiwakar1549, 10 months ago

Which mrna sequence results in a polypeptide that contains three amino acids?

Answers

Answered by faridkhann
0

Explanation:

What is the amino acid in position 118 that results from a single nucleotide insertion immediately following the three guanines that encode for glycine 116? In sickle-cell disease, the glutamic acid (Glu) at position number seven is mutated to valine (Val).

ANSWER 5' - CUU GAU ACU UAG - 3' 5' - UAU GCC CUA CGA - 3' 5' - AUC CAG UAA AAG - 3' 5' - GUC UGA CAC CGG - 3' 2.

Answered by monica789412
0

Nine mRNA sequence will result in a polypeptide of three amino acids.

Explanation:

mRNA is a sequence of nucleotides transcribed from DNA segment. mRNA contains sequences which code for genes and get translated into amino acids.

The triplet nucleotide sequence present on mRNA codes for an amino acid. There are 64 codons in the genetic code combinations.

The triplet codon present in exons, code for amino acid. Each amino acid bond together by condensation reaction to form peptide bonds resulting in polypeptide.

The mRNA sequence required to code for three amino acid long polypeptide will require nine nucleotide sequences or three triplet codon.

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