Question

which no. should be subtracted from each nos 13,25, and 55 so that resultant nos, are in continued proportion?​

Answer 1

Answer:

5 should be subtracted from each number 13,25 and 55 so that resultant numbers are in continued proportion

Step-by-step explanation:

Let the number to be subtracted be x.

Therefore 13−x, 25−x, 55−x are in continued proportion.

We know that If a:b::b:c, then a,b,c are in continued proportion, and c is the third proportional of a and b.  

=   $(b)^{2}$= ac

= $(25-x)^{2}=(13-x)*(55-x)$              

  Applying Identities we get

= $a^{2} -50a+625 = a^{2}-68a+715$                          

=$a^{2} -a^{2}-50a+68a = 715-625$

= 18a = 90

= a = 90/18

= a = 5

Therefore 5 needs to be subtracted from 13,25,55 such that they are in continued proportion.

Verification

= (13-5),(25-5),(55-5)

= 8,20 and 50

=8:20::20:50

As we know product of means (20 and 20) is equal to product of extremes (8 and 50).

20*20 = 8*50

400=400

LHS=RHS

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Answer 2

Step-by-step explanation:

this is very easy hope it helps u