Question

Which non-metal forms an oxide xo with a relative molecular mass of 60?

Answer 1

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Percent of oxygen in first oxide = 50%

Percent of metal in first oxide = 50%

Let the atomic mass of the metal be m g

Molecular mass of first oxide ‘XO2’ = m + 16x2 = (m+32)g

Percentage of oxygen by mass in the first oxide = 32/(m+32)*100 = 50

On solving mass of metal m = 32 g

Determination of the formula of second oxide

Element % At. mass relative no.of atoms simple ratio simplest whole no. ratio

1. Metal 40 32 40/32 = 1.25 1.25/1.25 =1.0 1.0 x1 =1

2. Oxygen 60 16 60/16 = 3.75 3.75/1.25 = 3.0 3.0x1 =3

So the formula of second oxide is XO3

Answer 2

Answer:

Oxygen is a non-metal forms an oxide xo with a relative molecular mass of 60....

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