Question

which number if an Ap 8,14,20,26,.....is72 more than its 41 st term?​

Answer 1

Answer:

Step-by-step explanation:

AP = 8 , 14 , 20 , 26 , ...........72

a  =  8

n = 41

d  =  6

we know that

$a_{n}=a+(n-1)d}\\a_{n}-a_{41}=72\\ a+(n-1)d-[a+(41-1)d]=72\\ a+nd-d-(a+40d)=72\\ a+nd-d-a-40d=72\\\ind-41d = 72\\d(n-41)=72\\ n-41 =\dfrac{72}{6}$

$n-41=12\\\\n=12+41\\\\n=53$