Question

which number must be added to each of the numbers 7 and 13 so that the resultant numbers will be in the ratio 2:3
A) 1
B) 2
C) 3
D) 4​

Answer 1

Answer:

let X be a common factor

then the resultant numbers are 2X and 3X

let Y be the number which is added to both numbers 7 and 13.

then,

7+Y=2X => Y=2X-7 ---------(1)

13+Y=3X => Y=3X-13 --------(2)

comparing eqn 1 and 2,

2X-7=3X-13

=>X=6

from eqn 1,

Y=2(6)-7 = 5

So the number which must be added is 5.

Answer 2

Given : Number added to 7 and 13 so that the resultant numbers will be in the ratio 2:3

To Find :  Number  

A) 1

B) 2

C) 3

D) 4​

Solution:

Let say Number added = N

=> ( 7 + N)  :  (13  + N )  =   2  :  3

=> ( 7 + N ) / ( 13 + N )  = 2/3

=> 3(7 + N )  = 2 ( 13 + N )

=> 21 + 3N  = 26  + 2N

=>  N   = 5

5 is the correct answer

None of the given options are correct

7 + 5 = 12

13 + 5 = 18

12 : 18

2 : 3

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