Question

which numbers should be added from 12, 16 and 21 so that resultant numbers are in continued proportion?​

Answer 1

Answer:

-4 should be subtracted from 12 ,16 and 21 so the number remains in continued proportion

Step-by-step explanation:

12-x/16-x=16-x/21-x(16-x)^2=(12-x)(21-x)

256 +x^2 -32 = 252 -33x +x^2

-32 + 33x=252-256

x=-4