Question

Which of following

solutions will have maximum boiling point

elevation and which have minimum freezing

point depression assuming the complete

dissociation? (a) 0.1 m KCl
(b) 0.05 m NaCl

(c) 1m AlPO4

(d) 0.1 m MgSO4​

Answer 1

$\huge\underline{\underline\mathtt{Answer:-}}$

Solution : Boiling point elevation and

freezing point depression are colligative

properties that depend on number of particles

in solution. The solution having more number of particles will have large boiling point elevation and that having less number of particles would show minimum freezing point depression.

(a) KCl K⊕ + Cl

0.1m 0.1m 0.1m solution = 0.2 mol

(b) NaCl Na⊕ + Cl

0.05m 0.05m 0.05m solution = 0.1 mol

(c) AlPO4 Al3⊕ + PO43

1m 1m 1m solution = 2.0mol

(d) MgSO4 Mg2⊕ + SO42

0.1m 0.1m 0.1m solution = 0.2mole

AlPO4

solution contains highest moles and hence highest number particles and in turn, the maximum ∆Tb

. NaCl solution has minimum moles and particles. It has minimum ∆Tf

Answer 2

Answer:

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