Question

Which of following transition of electron will produce photon of maximum wavelength in H-atom?


5 → 1


6 → 1


3 → 2


7 → 6

Answer 1

Answer:

wavelength is inversely proportional to energy.

energy is minimum in 7 to 6 transition

so the wavelength will be maximum in transition from 7 to 6

Answer 2

The transition of electron that will produce photon of maximum wavelength in H-atom is 7 → 6.

Given,

Transitions of the electron:5 → 1, 6 → 1, 3 → 2 and 7 → 6.

To find,

the transition of electron that will produce photon of maximum wavelength in H-atom.

Solution:

• This phenomenon is that of Hydrogen spectrum. It is a line spectrum applicable for only mono-electronic species.
• The wavelength, λ of a photon that gets emitted when an electron moves from a lower energy level to higher energy level or vice versa is given as per the following expression:
• $\frac{1}{(lambda)} =RZ^{2}(\frac{1}{n1^{2} }-\frac{1}{n2^{2} } )$.
• where, R-Rydberg's constant, n1-lower energy level, n2-higher energy level and Z-atomic number.
• For the wavelength of the photon to be maximum the energy gap due to the transition of the electron should be minimum.
• Thus, the transition should be from, n1=n to n2=(n+1) and vice-versa.

As there are two transitions, the transition that produces minimum energy gap among the two of them is 7 → 6.

Hence, 7 → 6 will produce the maximum wavelength photon.

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