Question

which of root2 and 2 is a zero of the polynomial p(X)=xcube-2x



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Answer 1

Answer:

root 2

Step-by-step explanation:

$p(x) = {x}^{3 } - 2x \\ p( \sqrt{2} ) = {( \sqrt{2} )}^{3 } - 2 \sqrt{2} \\ p( \sqrt{2} ) = 2 \sqrt{2} - 2 \sqrt{2} \\ p( \sqrt{2} ) = 0 \\ \\ now \: putting \: 2 \\ p(2) = {2}^{3 } - 2(2) \\ p(2) = \: 8 - 4 \\p(2) =4$

root2 is a zero of given polynomial not 2