Question

Which of the 2 rooms is bigger, one whose length and breadth of the floor are 12 m and 9.5 me
another whose length and breadth of the floor are 10 and 8.5 m?
rectangle and square:​

Answer 1

Answer:

Answer : 1st room floor is bigger

Step-by-step explanation:

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Answer 2

Given:

• Length and Breadth of f1st Rectangle are 12m and 9.5m respectively
• Length and Breadth of 2nd Rectangle are 10m and 8.5m respectively

Find:

• Which room is bigger

Solution:

we, know that

$\boxed{ \rm Area \: of \: rectangle = l \times b}$

For 1st Rectangle

$\setlength{\unitlength}{0.25cm}\begin{picture}(5,5)\thicklines\multiput(0,0)(24,0){2}{\line(0,1){7}}\multiput(0,0)(0,7){2}{\line(1,0){24}}\put(10,-2){\sf{12m}}\put(25,3){\sf{9.5m}} \put(23,7.2){\sf{A}}\put(0.1,7.2){\sf{B}} \put(0.1, - 1){\sf{C}} \put(23, - 1){\sf{D}} \end{picture}$

$\dashrightarrow\rm Area \: of \: rectangle = l \times b$

where,

• Length, l = 12m
• Breadth, b = 9.5m

So,

$\dashrightarrow\rm Area \: of \: rectangle = l \times b$

$\dashrightarrow\rm Area \: of \: rectangle = 12 \times 9.5$

$\dashrightarrow\rm Area \: of \: rectangle = 114 {m}^{2}$

$\therefore\rm Area \: of \: rectangle = 114 {m}^{2}$

_________________________

For 2nd Rectangle

$\setlength{\unitlength}{0.25cm}\begin{picture}(5,5)\thicklines\multiput(0,0)(24,0){2}{\line(0,1){7}}\multiput(0,0)(0,7){2}{\line(1,0){24}}\put(10,-2){\sf{10m}}\put(25,3){\sf{8.5m}} \put(23,7.2){\sf{E}}\put(0.1,7.2){\sf{F}} \put(0.1, - 1){\sf{G}} \put(23, - 1){\sf{H}} \end{picture}$

$\dashrightarrow\rm Area \: of \: rectangle = l \times b$

where,

• Length, l = 10m
• Breadth, b = 8.5m

So,

$\dashrightarrow\rm Area \: of \: rectangle = l \times b$

$\dashrightarrow\rm Area \: of \: rectangle = 10 \times 8.5$

$\dashrightarrow\rm Area \: of \: rectangle = 85 {m}^{2}$

$\therefore\rm Area \: of \: rectangle = 85{m}^{2}$

_________________________

Here, we can see directly that the area if f1st Rectangle is greater than the 2nd one.

So, 114m² > 85m²

F1st Rectangle > 2nd Rectangle