which of the A. P. 2½,4,5½,...is 31 ? Find also 10th term?
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Answered by
1
a10= a (n-1)d
2.5(10-1)1.5
2.5 (9)1.5
16
2.5(10-1)1.5
2.5 (9)1.5
16
Answered by
2
Hi ,
Given A.p is 2 1/2 , 4 , 5 1/2 ,...,31
First term ( a ) = 2 1/2 = 5/2 = 2.5
d = a2 - a1
= 4 - 2.5 = 1.5
an = 31
a + ( n - 1 )d = 31
2.5 + ( n - 1 ) ( 1.5 ) = 31
( n - 1 ) ( 1.5 ) = 31 - 2.5
n - 1 = 28.5/1.5
n - 1 = 19
n = 19 + 1
n = 20
2 )10th term = a10
= a + 9d
= 2.5 + 9 ( 1.5 )
= 2.5 + 13.5
= 16
I hope this helps you.
:)
Given A.p is 2 1/2 , 4 , 5 1/2 ,...,31
First term ( a ) = 2 1/2 = 5/2 = 2.5
d = a2 - a1
= 4 - 2.5 = 1.5
an = 31
a + ( n - 1 )d = 31
2.5 + ( n - 1 ) ( 1.5 ) = 31
( n - 1 ) ( 1.5 ) = 31 - 2.5
n - 1 = 28.5/1.5
n - 1 = 19
n = 19 + 1
n = 20
2 )10th term = a10
= a + 9d
= 2.5 + 9 ( 1.5 )
= 2.5 + 13.5
= 16
I hope this helps you.
:)
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