which of the ap is 5/6, 1, 7/6 is 3? answer in detail
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here
a=5/6
d= 1-(5/6) = 1/6
using the formula
a(n)= a + (n-1)d
3= 5/6 +(n-1)×1/6
3-5/6 =(n-1)×1/6
13/6 = (n-1)× 1/6
→ n-1 = 13/6 × 6/1
n-1 = 13
n = 13+1 = 14
so the 14th term in the AP is 3
a=5/6
d= 1-(5/6) = 1/6
using the formula
a(n)= a + (n-1)d
3= 5/6 +(n-1)×1/6
3-5/6 =(n-1)×1/6
13/6 = (n-1)× 1/6
→ n-1 = 13/6 × 6/1
n-1 = 13
n = 13+1 = 14
so the 14th term in the AP is 3
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