Which of the following aqueous solutions at the same temperature are not isotonic with one another?
1) 0.15 M urea
2) 0.05 M CaCl2
3) 0.1M MgSO4
4) 0.15 M glucose
i will mrk you as brainliest for sure .. but pls give me explanation on how you got that answer
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Answer:
Option 3 is correct. 0.1 M MgSO4 is not isotonic with others. This is because it's osmotic pressure value is different from them.
Explanation:
Van't Hoff Equation,
π = i×CRT
Where i = Ionization constant, C = molar concentration
For Urea and Glucose i = 1, for CaCl2 it is 3 and for MgSO4 it is 2.
π for 0.15 M Urea = 1 × 0.15 × RT = 0.15RT
π for 0.05 M CaCl2 = 3 × 0.05 × RT = 0.15RT
π for 0.01M MgSO4 = 2 × 0.01 × RT = 0.02 RT
π for 0.15 M glucose = 1 × 0.15 × RT = 0.15RT
Hence, option 3 is correct. 0.1M MgSO4 is not isotonic with other three solutions.
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Option 3 is correct. 0.1 M MgSO4 is not isotonic with others. This is because it's osmotic pressure value is different from them.
Explanation:
Van't Hoff Equation,
π = i×CRT
Where i = Ionization constant, C = molar concentration
For Urea and Glucose i = 1, for CaCl2 it is 3 and for MgSO4 it is 2.
π for 0.15 M Urea = 1 × 0.15 × RT = 0.15RT
π for 0.05 M CaCl2 = 3 × 0.05 × RT = 0.15RT
π for 0.01M MgSO4 = 2 × 0.01 × RT = 0.02 RT
π for 0.15 M glucose = 1 × 0.15 × RT = 0.15RT
Hence, option 3 is correct. 0.1M MgSO4 is not isotonic with other three solutions.
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