Which of the following are APs?If they form an AP,find the common difference d and wriye three more terms√3,√6,√9,√12,....
Answers
Answered by
1
Answer:
It's not an AP
Step-by-step explanation:
a1-a=a2-a1......
a=root 3
a1=root 6
a2=root 9
root 9=3
root 12= 2root3
Since, we can't find the difference of roots
hence,it is not an AP
Answered by
2
Answer:
It's not a A.P
Step-by-step explanation:
becuse in an a.p
conditions for terms in a.p
√3,√6,√9,√12......
d1=t2-t1
=√6-√3
=√3×√2-√3
=√3(√2-1)
d2=t3-t2
=√9-√6
=√3×√3-√3×√2
=√3(√3-√2)
d1 is not equal to d2 . so it is not an A.P
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