Chemistry, asked by karishkannan0128, 2 months ago

Which of the following are eigen functions of d/dx?

log(x)

exp(x)

sin(x)

xn​

Answers

Answered by allysia
2

Answer:

b) exp(x)

Explanation:

For eigen function:

\\\tt \Omega \psi = \omega \psi

Where on applying operator \\\tt \Omega on function \\\tt \psi returns a constant \\\tt \omega times the function itself.

Comparing each option one by one:

  1. \dfrac{d( \log x)}{dx} = \dfrac{1}{x}   # is not.
  2. \\\tt \dfrac{d( e^x)}{dx} = 1 . e^x # is
  3. \\\tt \dfrac{d \ sinx }{dx} =cos(x) #is not
  4. \\\tt \dfrac{d(xn)}{dx} =n # is not.

Answered by krishankumarmeel31
0

Answer:

b) exp(x)

Explanation:

For eigen function:

\begin{gathered}\\\tt \text{\O}mega \psi = \omega \psi\end{gathered}

Ømegaψ=ωψ

Where on applying operator \begin{gathered}\\\tt \text{\O}mega\end{gathered}

Ømega

on function \begin{gathered}\\\tt \psi\end{gathered}

ψ

returns a constant \begin{gathered}\\\tt \omega\end{gathered}

ω

times the function itself.

Comparing each option one by one:

\dfrac{d( \log x)}{dx} = \dfrac{1}{x}

dx

d(logx)

=

x

1

# is not.

\begin{gathered}\\\tt \dfrac{d( e^x)}{dx} = 1 . e^x\end{gathered}

dx

d(e

x

)

=1.e

x

# is

\begin{gathered}\\\tt \dfrac{d \ sinx }{dx} =cos(x)\end{gathered}

dx

d sinx

=cos(x)

#is not

\begin{gathered}\\\tt \dfrac{d(xn)}{dx} =n\end{gathered}

dx

d(xn)

=n

# is not.

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