Question

which of the following are in AP's 2,4,8,16--------​

Answer 1

a1= 2, a2 = 4, a3=8, a4=16

d= a2-a1

=4-2

=3

d2= a3-a2

=8-4

=4

Since d1 is not equal to d2, therefore it is not in AP.

Answer 2

a1 =2 , a2= 4 , a3= 8, a4=16

d1 = >a2-a1 = 4 - 2 = 2

d2 => a3 - a2 = 8 - 4 = 4

since d1 is not equal to d2

so, this is not an AP