Question

which of the following are polynomial
$1) ⅓x³+1 \\ 2) 5²-y²-2 \\ 3) 4x-3+3y \\ 4) 3x²-√2​$
​

Answer 1

Answer:

1,2,4

Step-by-step explanation:

3 is not because it does not have term eith degree 2

Answer 2

Step-by-step explanation:

Step-by-step explanation:(i) In 4x

Step-by-step explanation:(i) In 4x 2

Step-by-step explanation:(i) In 4x 2 −3x+7. all the indies of x are whole numbers. So, it is a polynomial in one variable x.

Step-by-step explanation:(i) In 4x 2 −3x+7. all the indies of x are whole numbers. So, it is a polynomial in one variable x.(i i) In y

i) In y 2

i) In y 2 +

i) In y 2 + 2

i) In y 2 + 2 the index of y is a whole number. So, it is a polynomial in one variable y.

i) In y 2 + 2 the index of y is a whole number. So, it is a polynomial in one variable y.(i i i ) In 3

) In 3 t

) In 3 t +t

) In 3 t +t 2

) In 3 t +t 2 =3t

) In 3 t +t 2 =3t 2

) In 3 t +t 2 =3t 21

) In 3 t +t 2 =3t 21

) In 3 t +t 2 =3t 21 +

) In 3 t +t 2 =3t 21 + 2

) In 3 t +t 2 =3t 21 + 2 t, here the exponent of first term is

) In 3 t +t 2 =3t 21 + 2 t, here the exponent of first term is 2

) In 3 t +t 2 =3t 21 + 2 t, here the exponent of first term is 21

) In 3 t +t 2 =3t 21 + 2 t, here the exponent of first term is 21 , which is not whole number therefore is it not a polynomial.

) In 3 t +t 2 =3t 21 + 2 t, here the exponent of first term is 21 , which is not whole number therefore is it not a polynomial.(i v) In y+

v) In y+ y

v) In y+ y2

v) In y+ y2 =y+2y

v) In y+ y2 =y+2y −1

v) In y+ y2 =y+2y −1 , here the exponent of first term is −1, which is not whole number, therefore, is it not a polynomial.

v) In y+ y2 =y+2y −1 , here the exponent of first term is −1, which is not whole number, therefore, is it not a polynomial.(v) In x

v) In y+ y2 =y+2y −1 , here the exponent of first term is −1, which is not whole number, therefore, is it not a polynomial.(v) In x 10

v) In y+ y2 =y+2y −1 , here the exponent of first term is −1, which is not whole number, therefore, is it not a polynomial.(v) In x 10 +y

v) In y+ y2 =y+2y −1 , here the exponent of first term is −1, which is not whole number, therefore, is it not a polynomial.(v) In x 10 +y 3

v) In y+ y2 =y+2y −1 , here the exponent of first term is −1, which is not whole number, therefore, is it not a polynomial.(v) In x 10 +y 3 +t

v) In y+ y2 =y+2y −1 , here the exponent of first term is −1, which is not whole number, therefore, is it not a polynomial.(v) In x 10 +y 3 +t 50

v) In y+ y2 =y+2y −1 , here the exponent of first term is −1, which is not whole number, therefore, is it not a polynomial.(v) In x 10 +y 3 +t 50 is not a polynomial in one variable as three variable x,y and t occur in it.