Question

which of the following are quadratic equations? 1)x+1/x=x² 2).x²–3x=0 3)(2x+1)(3x+2)=6(x–1)(x–2) 4)x(x+1)+8=(x+2)(x–2)​

Answer 1

Answer:

Option 2) x²–3x=0

Step-by-step explanation:

In algebra, a quadratic equation is any equation that can be rearranged in standard form as where x represents an unknown, and a, b, and c represent known numbers, where a ≠ 0: ax^2+bx+c=0

So lets see which option satisfies the above rule.

1) x+1/x=x²  => x^2+1=x^3 => x^3-x^2-1=0 => NO because of x^3

2) x²–3x=0  => YES it is in the format ax^2+bx+c=0, where c=0

3) (2x+1)(3x+2)=6(x–1)(x–2)  => 6x^2+7x+2=6x^2-18x+12 => 25x-10=0 => NO as a=0

4) x(x+1)+8=(x+2)(x–2)​ => x^2+x+8=x^2-4 => x+12=0 => NO as a=0