which of the following are the root of 3x²+2x-1 =0?
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Answered by
16
Heya☺
3x^2 + 2x -1 =0
3x^2 + 3x - x -1 =0
3x(x+1) -1 (x+1)=0
(3x-1) (x+1) =0
x = 1/3 , -1
Therefore both 1st and 2nd options are right
3x^2 + 2x -1 =0
3x^2 + 3x - x -1 =0
3x(x+1) -1 (x+1)=0
(3x-1) (x+1) =0
x = 1/3 , -1
Therefore both 1st and 2nd options are right
Answered by
8
heyaa
here is your answer
3x² +2x -1=0
3x² + 3x -x -1=0
3x (x +1) -1(x+1) = 0
(3x-1)(x+1)=0
x = -1 , 1/3
therefore, (1) and (2) are the zeroes of the given polynomial
hope it helps
here is your answer
3x² +2x -1=0
3x² + 3x -x -1=0
3x (x +1) -1(x+1) = 0
(3x-1)(x+1)=0
x = -1 , 1/3
therefore, (1) and (2) are the zeroes of the given polynomial
hope it helps
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