Question

which of the following are the roots of 3xsquare + 2x - 1 = 0

Answer 1

Answer:

$(x=\frac{1}{3})......or........(x=-1)$

Step-by-step explanation:

$3x^2 + 2x - 1 = 0 \\3x^2 +3x-x -1=0\\3x(x+1)-1(x+1)=0\\(3x-1)(x+1)=0\\(3x-1)=0.....or.......(x+1)=0\\(x=\frac{1}{3})......or........(x=-1)$

Answer 2

Answer:

(-1) and 1/3 are required roots

Step-by-step explanation:

3x^2+2x-1

=3x^2+3x-x-1

3x(x+1)-1(x+1)

(x+1) (3x-1)

To find roots ,put 3x^2+2x-1

=0

Either,x+1=0 or 3x-1=0

x=-1 or x=1/3

THEREFORE, (-1) and 1/3 are

the required roots

HOPE THIS ANSWER HELPS YOU