Which of the following atom has an odd number of neutron?
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QUESTION:-
Which of the following atom has an odd number of neutrons?
(a) 11B
(b) 14N
(c) 23Na
ANSWER:-
- (b) 14N is the correct option.
EXPLANATION:-
- The mass number of an atom is = the sum of the number of protons and the number of neutrons. And the number of Neutrons and Electrons is equal
- N = Nitrogen, B = Boron, Na = Sodium.
Boron (B) has (Proton + neutron) is 11 and Proton is 5 so, Neutrons = (Proton + neutron) - Proton
= 11 - 5 = 6 and 6 is even.
Nitrogen (N) has (Proton + neutron) is 14 and Protons 7 so, Neutrons = (Proton + neutron) - Proton = 14 - 7 = 7 and 7 is odd.
Sodium (Na) has (Proton + neutron) is 23 and Protons 11 so, Neutrons = (Proton + neutron) - Proton = 23 - 11 = 12 and 12 is even.
Hence, the 14N (nitrogen) atom has an odd number of neutron
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